4[3(x-5)+7]=12x-32

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Solution for 4[3(x-5)+7]=12x-32 equation: 


Simplifying
4[3(x + -5) + 7] = 12x + -32

Reorder the terms:
4[3(-5 + x) + 7] = 12x + -32
4[(-5 * 3 + x * 3) + 7] = 12x + -32
4[(-15 + 3x) + 7] = 12x + -32

Reorder the terms:
4[-15 + 7 + 3x] = 12x + -32

Combine like terms: -15 + 7 = -8
4[-8 + 3x] = 12x + -32
[-8 * 4 + 3x * 4] = 12x + -32
[-32 + 12x] = 12x + -32

Reorder the terms:
-32 + 12x = -32 + 12x

Add '32' to each side of the equation.
-32 + 32 + 12x = -32 + 32 + 12x

Combine like terms: -32 + 32 = 0
0 + 12x = -32 + 32 + 12x
12x = -32 + 32 + 12x

Combine like terms: -32 + 32 = 0
12x = 0 + 12x
12x = 12x

Add '-12x' to each side of the equation.
12x + -12x = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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